E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
Daily Literature Deviations is a group that is dedicated to bringing literature to the forefront of the deviantArt community. We attempt to accomplish this by daily featuring Literature artists from around the community that deserve the recognition, but are not getting it.
Each day we will feature 10 deviations from the Literature categories in a News Article. In order to support the artists that we feature, we ask that you the news article as well as check out the individual pieces. We understand that each day you may not be able to check out each and every one of the pieces, everyone has their own things going on. We just ask that you make an attempt to help support the growing Literature community.
When it comes to community spirit, `Rushy is a shining example. From participating in devmeets, to providing positive encouragement to other artists, `Rushy can always be found demonstrating what it really takes to be a true deviant. It's without any hesitation that we are delighted to award the Deviousness Award for July 2009 to `RushyRead More
Devious Comments
Comments
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"i am ninja, she is ninja, he is ninja too, i am ninja , we are ninja, i can't believe that you are ninja too!"
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-cmalidore
for me, a polished version have same great quality than this!
great work man!
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Sorry for my bad english.
My Webpage |
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"...so paradoxically you can appreciate all art." Yes, paradoxically anything is correct.
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RESPECT THAT!
I'll let a fave do the res of the talking for me.
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Did you know that:
E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
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Have a very nice and productive day!
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